-20y^2+13y-2=0

Solution for -20y^2+13y-2=0 equation:

-20y^2+13y-2=0

a = -20; b = 13; c = -2;
Δ = b2-4ac
Δ = 132-4·(-20)·(-2)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-3}{2*-20}=\frac{-16}{-40}
=2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+3}{2*-20}=\frac{-10}{-40}
=1/4
$